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Boiler Steam Efficiency & Fuel Ratio Calculator

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Paste this where you want the calculator to appear. It works on any site — WordPress, Squarespace, Webflow, Ghost or plain HTML — and needs no JavaScript of yours. It carries a link back here, which is the only thing we ask for it.

See what it looks like

Steam per kilogram of fuel is the number the boiler house can see hourly. Efficiency is the same truth in the units the energy manager wants.

Steam Side Output
kg/h
kJ/kg
kJ/kg
Fuel Side Input
kg/h
kJ/kg

Coal ≈20,000; furnace oil ≈40,000; biomass ≈15,000.

/kg
h/yr

Boiler Efficiency

— %

Direct method: heat into steam over heat in fuel

Heat Balance & Cost

Steam to Fuel Ratio
— kg/kg
Heat Into Steam
— kW
Heat In Fuel
— kW
Heat Lost
— kW
Fuel Cost per Tonne of Steam
— /t
Annual Fuel Cost
— /yr

The direct method carries the error of both meters and says nothing about where the losses go — for that, run the indirect (heat loss) method with a flue gas analysis. An efficiency above about 92% on the direct method almost always means a mis-metered fuel or steam flow rather than an exceptional boiler.

Using this calculator

About the Boiler Steam Efficiency & Fuel Ratio Calculator

The formula

This is the expression the tool evaluates. Every term is named underneath, with the unit it must be supplied in.

Boiler Efficiency
efficiency = f( steamOutput, steamEnthalpy, feedwaterEnthalpy, fuelConsumption, fuelCalorific, fuelPrice, operatingHours )

Each input feeds the expression evaluated in the browser; the symbol table below names every term and its unit.

Symbols used above
SymbolStands forUnit
steamOutputSteam Outputkg/h
steamEnthalpySteam EnthalpykJ/kg
feedwaterEnthalpyFeedwater EnthalpykJ/kg
fuelConsumptionFuel Consumptionkg/h
fuelCalorificFuel Calorific ValuekJ/kg
fuelPriceFuel Price/kg
operatingHoursOperating Hoursh/yr
efficiencyBoiler Efficiency%
steamToFuelRatioSteam to Fuel Ratiokg/kg
heatToSteamHeat Into SteamkW
heatInputHeat In FuelkW
lossesHeat LostkW
fuelCostPerTonneSteamFuel Cost per Tonne of Steam/t
annualFuelCostAnnual Fuel Cost/yr

How the result is derived

Step by step, from the values you type to the figure on screen.

  1. The 7 inputs are read from the form on every keystroke: Steam Output, Steam Enthalpy, Feedwater Enthalpy, Fuel Consumption, Fuel Calorific Value, Fuel Price and Operating Hours.
  2. Each value is checked against the accepted range in the input table below. A value outside its range stops the calculation rather than producing a misleading figure — the results blank out and a message appears.
  3. The validated values are substituted into the expression above, which resolves Boiler Efficiency together with every supporting figure in one pass — no value is carried over from a previous entry.
  4. The supporting outputs — Steam to Fuel Ratio, Heat Into Steam, Heat In Fuel, Heat Lost, Fuel Cost per Tonne of Steam and Annual Fuel Cost — come from the same pass, so they always describe the same case as the headline figure.
  5. Results are rounded for display only. The full-precision value is used throughout the chain, so reading a rounded intermediate figure back into the tool by hand can shift the last digit.

What each input means

Where to read each value on the floor, the unit it must be in, and the range the tool accepts.

InputUnitAccepted rangeDefaultWhat it means
Steam Outputkg/h100 to 200000 kg/h8000
Steam EnthalpykJ/kg2000 to 3500 kJ/kg2750
Feedwater EnthalpykJ/kg40 to 1000 kJ/kg420
Fuel Consumptionkg/h1 to 50000 kg/h1100
Fuel Calorific ValuekJ/kg5000 to 60000 kJ/kg20000Coal ≈20,000; furnace oil ≈40,000; biomass ≈15,000.
Fuel Price/kg0.001 to 10 /kg0.12
Operating Hoursh/yr100 to 8760 h/yr8000

What the tool returns

The headline figure and every supporting value it is built from.

OutputUnitWhat it tells you
Boiler Efficiency (headline result)%Direct method: heat into steam over heat in fuel
Steam to Fuel Ratiokg/kg
Heat Into SteamkW
Heat In FuelkW
Heat LostkW
Fuel Cost per Tonne of Steam/t
Annual Fuel Cost/yr

Worked example

Given

Steam Output
8000 kg/h
Steam Enthalpy
2750 kJ/kg
Feedwater Enthalpy
420 kJ/kg
Fuel Consumption
1100 kg/h
Fuel Calorific Value
20000 kJ/kg
Fuel Price
0.12 /kg
Operating Hours
8000 h/yr

The tool loads with this case already solved — the Boiler Efficiency shown above is its answer. Change one value and the difference from this baseline is the sensitivity of the result to that variable.

How to use it

  1. Work through the input groups in order — Steam Side and Fuel Side. The defaults are a realistic case, so you can change one value at a time and watch what moves.
  2. There is no calculate button. Every figure recalculates as you type or drag, which is what makes this usable for a what-if sweep rather than a single answer.
  3. Read Boiler Efficiency in the dark results panel — that is the headline figure, expressed in %.
  4. Check the supporting rows underneath (Steam to Fuel Ratio, Heat Into Steam, Heat In Fuel, Heat Lost, Fuel Cost per Tonne of Steam and Annual Fuel Cost) before acting on the headline — they are where an implausible input usually shows itself first.
  5. Reset to defaults returns every field to the reference case, which is the quickest way to check whether a surprising result came from the tool or from an input you had changed earlier.

Where this is used

  • Process planning — establishing Boiler Efficiency before a trial is booked, so machine time and material in Sustainability, ETP & Utilities are committed against a calculated figure rather than an estimate.
  • Costing and quotation — Boiler Efficiency is an input to the cost sheet, and quoting from a worked number rather than a remembered one is what keeps a margin intact.
  • Troubleshooting — when the floor result drifts from plan, entering the measured values (starting with Steam Output) shows how much of the gap in Boiler Efficiency each variable explains.
  • Teaching and study — the accepted ranges bracket normal Sustainability, ETP & Utilities practice, so moving one variable at a time shows the shape of the relationship rather than a single answer.

Assumptions and limits

  • The direct method carries the error of both meters and says nothing about where the losses go — for that, run the indirect (heat loss) method with a flue gas analysis. An efficiency above about 92% on the direct method almost always means a mis-metered fuel or steam flow rather than an exceptional boiler.
  • Every input is bounded to the range normal practice occupies (Steam Output 100 to 200000 kg/h, Steam Enthalpy 2000 to 3500 kJ/kg and Feedwater Enthalpy 40 to 1000 kJ/kg, and so on for the rest). Those bounds are guard rails against typing errors, not a claim that the formula fails one unit outside them.
  • The calculation is deterministic: the same inputs always give the same result. It carries no allowance for machine condition, operator skill, ambient conditions or lot-to-lot material variation unless an input above explicitly represents one.
  • Nothing is sent anywhere. The maths runs in your browser, so the numbers you type never leave the page.

Questions people ask

What do I need to know before using the Boiler Steam Efficiency & Fuel Ratio Calculator?

Have these to hand: Steam Output, Steam Enthalpy, Feedwater Enthalpy, Fuel Consumption, Fuel Calorific Value, Fuel Price and Operating Hours. With those entered, the tool returns Boiler Efficiency immediately.

What exactly is Boiler Efficiency?

Direct method: heat into steam over heat in fuel. It is reported in %. It is derived from Steam Output, Steam Enthalpy, Feedwater Enthalpy, Fuel Consumption, Fuel Calorific Value, Fuel Price and Operating Hours, and is the figure the rest of the Sustainability, ETP & Utilities calculation is built around.

Which units does this calculator expect?

Enter Steam Output in kg/h, Steam Enthalpy in kJ/kg, Feedwater Enthalpy in kJ/kg, Fuel Consumption in kg/h, Fuel Calorific Value in kJ/kg, Fuel Price in /kg and Operating Hours in h/yr. Mixing unit systems is the most common cause of a result that looks an order of magnitude wrong — convert before typing, not after reading.

What are the other figures under the main result?

They are the intermediate quantities the calculation passes through: Steam to Fuel Ratio, Heat Into Steam, Heat In Fuel, Heat Lost, Fuel Cost per Tonne of Steam and Annual Fuel Cost. They are shown because a headline number nobody can trace is a number nobody trusts — checking them against your own expectation is the fastest way to confirm the inputs were read as you intended.

Can I rely on this for a production decision?

The direct method carries the error of both meters and says nothing about where the losses go — for that, run the indirect (heat loss) method with a flue gas analysis. An efficiency above about 92% on the direct method almost always means a mis-metered fuel or steam flow rather than an exceptional boiler. Treat the output as an engineering estimate that narrows the trial window, not as a substitute for the trial.

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