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Exhaustion approaches equilibrium on a squared law, not a straight one. The last few percent cost more time than the first sixty.
Exhaustion at End of Cycle
—%
What the programmed hold actually reaches
Rate & Characteristic Times
Rate Constant K
—1/min
Sample as Share of Equilibrium
—%
Half-Dyeing Time
—min
Time to 95% of Equilibrium
—min
Time to 99% of Equilibrium
—min
Dye Left in Bath
—%
Extra Time Needed for 99%
—min
Dye Discharged per Tonne at 1% owf
—g
The fit uses one point, so it inherits everything that point carries: a sample drawn while the bath is still climbing to temperature describes a system that was never at the temperature the constant is supposed to belong to, and the resulting K will flatter the cycle. Draw the sample during the isothermal hold and take the equilibrium figure from a deliberately over-run laboratory dyeing rather than from the recipe sheet. Equilibrium exhaustion is a property of the whole system and moves with liquor ratio, electrolyte and temperature, so a constant fitted at one liquor ratio does not transfer to a machine running a different one - which is the usual reason a laboratory cycle fails to reproduce in bulk. The model describes exhaustion, not fixation: for reactive dyes a bath can be handsomely exhausted and still fix badly, and the hydrolysed fraction that follows is a wash-off problem rather than a kinetic one. Time to 99 percent is reported because it is a useful bound, not because it is a target; the last percent of equilibrium is almost never worth the steam, and the honest reading of a large extra-time figure is usually that the recipe should change rather than that the cycle should lengthen.
Using this calculator
About the Dyebath Exhaustion Kinetics & Cycle Time Fit
The formula
This is the expression the tool evaluates. Every term is named underneath, with the unit it must be supplied in.
The Cegarra-Puente relation-ln( 1 - (Et / Einf)^2 ) = K t
Linear in t, so a single measured pair fits K directly. The squared ratio is what produces the long approach to equilibrium.
Rearranged to predict exhaustion at any timeEt = Einf x sqrt( 1 - exp( -K t ) )
Used for the programmed cycle. Note that it approaches Einf, never 100 percent - equilibrium is the ceiling, not full exhaustion.
Time to any fraction of equilibriumt(f) = -ln( 1 - f^2 ) / K t(0.5) = ln(4/3) / K
Half-dyeing time is 0.288/K while 99 percent needs 3.917/K - a factor of thirteen between them, which is the tail in one number.
Symbols used above
Symbol
Stands for
Unit
sampleTime
Sampling Time
min
sampleExhaustion
Exhaustion at that Time
%
equilibriumExhaustion
Equilibrium Exhaustion
%
dyeingTime
Dyeing Time at Temperature
min
predictedExhaustion
Exhaustion at End of Cycle
%
rateConstant
Rate Constant K
1/min
fractionAtSample
Sample as Share of Equilibrium
%
halfDyeingTime
Half-Dyeing Time
min
timeTo95
Time to 95% of Equilibrium
min
timeTo99
Time to 99% of Equilibrium
min
unexhaustedDye
Dye Left in Bath
%
extraTimeFor99
Extra Time Needed for 99%
min
bathLossPerTonne
Dye Discharged per Tonne at 1% owf
g
How the result is derived
Step by step, from the values you type to the figure on screen.
The 4 inputs are read from the form on every keystroke: Sampling Time, Exhaustion at that Time, Equilibrium Exhaustion and Dyeing Time at Temperature.
Each value is checked against the accepted range in the input table below. A value outside its range stops the calculation rather than producing a misleading figure — the results blank out and a message appears.
The validated values are substituted into the expression above, which resolves Exhaustion at End of Cycle together with every supporting figure in one pass — no value is carried over from a previous entry.
The supporting outputs — Rate Constant K, Sample as Share of Equilibrium, Half-Dyeing Time, Time to 95% of Equilibrium, Time to 99% of Equilibrium, Dye Left in Bath, Extra Time Needed for 99% and Dye Discharged per Tonne at 1% owf — come from the same pass, so they always describe the same case as the headline figure.
Results are rounded for display only. The full-precision value is used throughout the chain, so reading a rounded intermediate figure back into the tool by hand can shift the last digit.
What each input means
Where to read each value on the floor, the unit it must be in, and the range the tool accepts.
Input
Unit
Accepted range
Default
What it means
Sampling Time
min
1 to 300 min
20
Minutes from the start of the isothermal hold
Exhaustion at that Time
%
1 to 99 %
62
From bath absorbance against the starting bath
Equilibrium Exhaustion
%
5 to 100 %
88
The most this dye-fibre-electrolyte system will ever give
Dyeing Time at Temperature
min
1 to 480 min
60
Isothermal hold in the programme, excluding the ramp
What the tool returns
The headline figure and every supporting value it is built from.
Output
Unit
What it tells you
Exhaustion at End of Cycle (headline result)
%
What the programmed hold actually reaches
Rate Constant K
1/min
Sample as Share of Equilibrium
%
Half-Dyeing Time
min
Time to 95% of Equilibrium
min
Time to 99% of Equilibrium
min
Dye Left in Bath
%
Extra Time Needed for 99%
min
Dye Discharged per Tonne at 1% owf
g
Worked example
Given
Sampling Time
20 min
Exhaustion at that Time
62 %
Equilibrium Exhaustion
88 %
Dyeing Time at Temperature
60 min
The tool loads with this case already solved — the Exhaustion at End of Cycle shown above is its answer. Change one value and the difference from this baseline is the sensitivity of the result to that variable.
How to use it
Work through the input groups in order — Measured Point and Programmed Cycle. The defaults are a realistic case, so you can change one value at a time and watch what moves.
There is no calculate button. Every figure recalculates as you type or drag, which is what makes this usable for a what-if sweep rather than a single answer.
Read Exhaustion at End of Cycle in the dark results panel — that is the headline figure, expressed in %.
Check the supporting rows underneath (Rate Constant K, Sample as Share of Equilibrium, Half-Dyeing Time, Time to 95% of Equilibrium, Time to 99% of Equilibrium, Dye Left in Bath, Extra Time Needed for 99% and Dye Discharged per Tonne at 1% owf) before acting on the headline — they are where an implausible input usually shows itself first.
Reset to defaults returns every field to the reference case, which is the quickest way to check whether a surprising result came from the tool or from an input you had changed earlier.
Where this is used
Process planning — establishing Exhaustion at End of Cycle before a trial is booked, so machine time and material in Dyeing, Printing, Color Management & Chemical Control are committed against a calculated figure rather than an estimate.
Costing and quotation — Exhaustion at End of Cycle is an input to the cost sheet, and quoting from a worked number rather than a remembered one is what keeps a margin intact.
Troubleshooting — when the floor result drifts from plan, entering the measured values (starting with Sampling Time) shows how much of the gap in Exhaustion at End of Cycle each variable explains.
Teaching and study — the accepted ranges bracket normal Dyeing, Printing, Color Management & Chemical Control practice, so moving one variable at a time shows the shape of the relationship rather than a single answer.
Assumptions and limits
The fit uses one point, so it inherits everything that point carries: a sample drawn while the bath is still climbing to temperature describes a system that was never at the temperature the constant is supposed to belong to, and the resulting K will flatter the cycle. Draw the sample during the isothermal hold and take the equilibrium figure from a deliberately over-run laboratory dyeing rather than from the recipe sheet. Equilibrium exhaustion is a property of the whole system and moves with liquor ratio, electrolyte and temperature, so a constant fitted at one liquor ratio does not transfer to a machine running a different one - which is the usual reason a laboratory cycle fails to reproduce in bulk. The model describes exhaustion, not fixation: for reactive dyes a bath can be handsomely exhausted and still fix badly, and the hydrolysed fraction that follows is a wash-off problem rather than a kinetic one. Time to 99 percent is reported because it is a useful bound, not because it is a target; the last percent of equilibrium is almost never worth the steam, and the honest reading of a large extra-time figure is usually that the recipe should change rather than that the cycle should lengthen.
Every input is bounded to the range normal practice occupies (Sampling Time 1 to 300 min, Exhaustion at that Time 1 to 99 % and Equilibrium Exhaustion 5 to 100 %, and so on for the rest). Those bounds are guard rails against typing errors, not a claim that the formula fails one unit outside them.
The calculation is deterministic: the same inputs always give the same result. It carries no allowance for machine condition, operator skill, ambient conditions or lot-to-lot material variation unless an input above explicitly represents one.
Nothing is sent anywhere. The maths runs in your browser, so the numbers you type never leave the page.
Questions people ask
What do I need to know before using the Dyebath Exhaustion Kinetics & Cycle Time Fit?
Have these to hand: Sampling Time, Exhaustion at that Time, Equilibrium Exhaustion and Dyeing Time at Temperature. With those entered, the tool returns Exhaustion at End of Cycle immediately.
What exactly is Exhaustion at End of Cycle?
What the programmed hold actually reaches. It is reported in %. It is derived from Sampling Time, Exhaustion at that Time, Equilibrium Exhaustion and Dyeing Time at Temperature, and is the figure the rest of the Dyeing, Printing, Color Management & Chemical Control calculation is built around.
Which units does this calculator expect?
Enter Sampling Time in min, Exhaustion at that Time in %, Equilibrium Exhaustion in % and Dyeing Time at Temperature in min. Mixing unit systems is the most common cause of a result that looks an order of magnitude wrong — convert before typing, not after reading.
What are the other figures under the main result?
They are the intermediate quantities the calculation passes through: Rate Constant K, Sample as Share of Equilibrium, Half-Dyeing Time, Time to 95% of Equilibrium, Time to 99% of Equilibrium, Dye Left in Bath, Extra Time Needed for 99% and Dye Discharged per Tonne at 1% owf. They are shown because a headline number nobody can trace is a number nobody trusts — checking them against your own expectation is the fastest way to confirm the inputs were read as you intended.
Can I rely on this for a production decision?
The fit uses one point, so it inherits everything that point carries: a sample drawn while the bath is still climbing to temperature describes a system that was never at the temperature the constant is supposed to belong to, and the resulting K will flatter the cycle. Draw the sample during the isothermal hold and take the equilibrium figure from a deliberately over-run laboratory dyeing rather than from the recipe sheet. Equilibrium exhaustion is a property of the whole system and moves with liquor ratio, electrolyte and temperature, so a constant fitted at one liquor ratio does not transfer to a machine running a different one - which is the usual reason a laboratory cycle fails to reproduce in bulk. The model describes exhaustion, not fixation: for reactive dyes a bath can be handsomely exhausted and still fix badly, and the hydrolysed fraction that follows is a wash-off problem rather than a kinetic one. Time to 99 percent is reported because it is a useful bound, not because it is a target; the last percent of equilibrium is almost never worth the steam, and the honest reading of a large extra-time figure is usually that the recipe should change rather than that the cycle should lengthen. Treat the output as an engineering estimate that narrows the trial window, not as a substitute for the trial.