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Failed Steam Trap Loss, Annual Cost & Survey Payback

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See what it looks like

A failed trap makes no noise and no alarm. It just passes a tonne of steam a week.

The Failure Orifice, pressure and how many
mm
bar g
h/yr
Cost & Carbon What the steam is worth
/t
%
kg/kWh

Steam Lost per Failed Trap

— kg/h

Napier choked flow through the orifice

Total Loss, Cost & Payback

Survey Payback
— months
Annual Cost of the Failures
—
Steam Lost
— t/yr
Total Loss Rate
— kg/h
Cost per Failed Trap
— /yr
Carbon from the Loss
— t CO2/yr
Boiler Fuel Wasted
— kWh/yr
Orifice Area
— mm2

The Napier relation assumes choked flow of dry saturated steam through a sharp-edged orifice, and gives an upper bound on the loss: a real trap that has failed partially open, or that cycles, passes less, and a trap passing a mixture of steam and condensate passes less again. Wet steam reduces the mass flow of live steam while raising the total. The orifice diameter should be the trap seat size from the manufacturer data, not the pipe bore. The 750 kWh per tonne is a representative enthalpy above feedwater and varies with pressure and feedwater temperature; for a precise fuel figure use steam tables at the actual conditions. Condensate not returned also carries a water treatment and blowdown cost that is not included here.

Using this calculator

About the Failed Steam Trap Loss, Annual Cost & Survey Payback

The formula

This is the expression the tool evaluates. Every term is named underneath, with the unit it must be supplied in.

Napier choked flow, in metric form
lossPerTrap = 0.2472 x orificeArea x ( steamPressureBarG + 1 )

Above about 1.9 times atmospheric the flow through an orifice chokes at sonic velocity and becomes proportional to absolute upstream pressure alone - the downstream pressure stops mattering. Napier captured that as a linear relation, and every steam-trap loss figure in industry derives from it.

Diameter enters squared
orificeArea = pi x ( orificeDiameter / 2 )^2

A 4 mm orifice loses 56% more than a 3.2 mm one at the same pressure, which is why trap sizing matters as much for the failure mode as for the duty. Oversized traps are common and they fail expensively.

Rate to annual money
annualCost = lossPerTrap x trapsFailed x hoursPerYear / 1000 x steamCostPerTonne

The loss is continuous whenever the line is live, which for a mill on 8,000 hours is nearly all year. That continuity is what makes a small orifice expensive - it is not a leak that gets fixed at the next shutdown, it is a permanent open valve.

Steam back to fuel at the boiler
boilerFuel = steamTonnes x 750 / boilerEfficiency x 100

A tonne of saturated steam carries roughly 750 kWh above feedwater, and the boiler had to burn more than that to make it. Carbon follows from the fuel, not from the steam, which is why the boiler efficiency belongs in the carbon figure.

Symbols used above
SymbolStands forUnit
NapierThe choked-orifice steam flow relation, W proportional to area x absolute pressure—
bar gGauge pressure - absolute is one bar higherbar g
failed openA trap passing live steam continuously rather than only condensate—

How the result is derived

Step by step, from the values you type to the figure on screen.

  1. The 8 inputs are read from the form on every keystroke: Trap Orifice Diameter, Steam Pressure, Traps Failed Open, Operating Hours, Steam Cost, Trap Survey Cost, Boiler Efficiency and Fuel Carbon Intensity.
  2. Each value is checked against the accepted range in the input table below. A value outside its range stops the calculation rather than producing a misleading figure — the results blank out and a message appears.
  3. The validated values are substituted into the expression above, which resolves Steam Lost per Failed Trap together with every supporting figure in one pass — no value is carried over from a previous entry.
  4. The supporting outputs — Survey Payback, Annual Cost of the Failures, Steam Lost, Total Loss Rate, Cost per Failed Trap, Carbon from the Loss, Boiler Fuel Wasted and Orifice Area — come from the same pass, so they always describe the same case as the headline figure.
  5. Results are rounded for display only. The full-precision value is used throughout the chain, so reading a rounded intermediate figure back into the tool by hand can shift the last digit.

What each input means

Where to read each value on the floor, the unit it must be in, and the range the tool accepts.

InputUnitAccepted rangeDefaultWhat it means
Trap Orifice Diametermm0.5 to 20 mm3.2
Steam Pressurebar g0.2 to 40 bar g7
Traps Failed Open—1 to 50012
Operating Hoursh/yr100 to 8760 h/yr8000
Steam Cost/t1 to 200 /t28
Trap Survey Cost—100 to 1000003500
Boiler Efficiency%50 to 98 %82
Fuel Carbon Intensitykg/kWh0.01 to 0.5 kg/kWh0.202

What the tool returns

The headline figure and every supporting value it is built from.

OutputUnitWhat it tells you
Steam Lost per Failed Trap (headline result)kg/hNapier choked flow through the orifice
Survey Paybackmonths
Annual Cost of the Failures—
Steam Lostt/yr
Total Loss Ratekg/h
Cost per Failed Trap/yr
Carbon from the Losst CO2/yr
Boiler Fuel WastedkWh/yr
Orifice Areamm2

Worked example

Given

0
3.2 mm orifice at 7 bar gauge
1
12 traps failed open, 8,000 operating hours
2
Steam at 28 per tonne, survey quoted at 3,500
3
Boiler 82% efficient on fuel at 0.202 kg CO2 per kWh

Substituting

area = pi x (3.2 / 2)^2 = 8.0425 mm2perTrap = 0.2472 x 8.0425 x 8 = 15.9048 kg/hannual = 15.9048 x 12 x 8,000 / 1,000 = 1,526.86 tcost = 1,526.86 x 28 = 42,752.11payback = 3,500 / 42,752.11 x 12 = 0.98 months

Answer

0
15.9048 kg/h per trap, 190.8576 kg/h in total
1
1,526.8611 tonnes of steam a year, costing 42,752.11
2
Survey pays back in 0.9824 months
3
3,562.68 a year per failed trap
4
1,396,519 kWh of boiler fuel and 282.0969 t CO2

Twelve traps the size of a pencil lead cost 42,752 a year, and the survey that finds them pays for itself in under a month. The Napier figure checks against the imperial standard: a one-eighth inch orifice at 100 psi is quoted at about 15.5 kg/h in every steam handbook, and this returns 15.9 for the metric equivalent.

How to use it

  1. Work through the input groups in order — The Failure and Cost & Carbon. The defaults are a realistic case, so you can change one value at a time and watch what moves.
  2. There is no calculate button. Every figure recalculates as you type or drag, which is what makes this usable for a what-if sweep rather than a single answer.
  3. Read Steam Lost per Failed Trap in the dark results panel — that is the headline figure, expressed in kg/h.
  4. Check the supporting rows underneath (Survey Payback, Annual Cost of the Failures, Steam Lost, Total Loss Rate, Cost per Failed Trap, Carbon from the Loss, Boiler Fuel Wasted and Orifice Area) before acting on the headline — they are where an implausible input usually shows itself first.
  5. Reset to defaults returns every field to the reference case, which is the quickest way to check whether a surprising result came from the tool or from an input you had changed earlier.

Where this is used

  • Process planning — establishing Steam Lost per Failed Trap before a trial is booked, so machine time and material in Sustainability, ETP & Utilities are committed against a calculated figure rather than an estimate.
  • Costing and quotation — Steam Lost per Failed Trap is an input to the cost sheet, and quoting from a worked number rather than a remembered one is what keeps a margin intact.
  • Troubleshooting — when the floor result drifts from plan, entering the measured values (starting with Trap Orifice Diameter) shows how much of the gap in Steam Lost per Failed Trap each variable explains.
  • Teaching and study — the accepted ranges bracket normal Sustainability, ETP & Utilities practice, so moving one variable at a time shows the shape of the relationship rather than a single answer.

Reading the result

Typical bands and what each one is telling you.

ValueWhat it indicates
10 - 20% of traps failedTypical for a plant with no survey programme.
Under 5% failedA managed programme with annual or biennial survey.
Payback under 3 monthsNormal. Trap surveys are among the shortest-payback utility measures available.
3 - 5 mm orificeCommon range for thermodynamic and float traps on mill distribution.

Assumptions and limits

  • The Napier relation assumes choked flow of dry saturated steam through a sharp-edged orifice, and gives an upper bound on the loss: a real trap that has failed partially open, or that cycles, passes less, and a trap passing a mixture of steam and condensate passes less again. Wet steam reduces the mass flow of live steam while raising the total. The orifice diameter should be the trap seat size from the manufacturer data, not the pipe bore. The 750 kWh per tonne is a representative enthalpy above feedwater and varies with pressure and feedwater temperature; for a precise fuel figure use steam tables at the actual conditions. Condensate not returned also carries a water treatment and blowdown cost that is not included here.
  • Every input is bounded to the range normal practice occupies (Trap Orifice Diameter 0.5 to 20 mm, Steam Pressure 0.2 to 40 bar g and Traps Failed Open 1 to 500, and so on for the rest). Those bounds are guard rails against typing errors, not a claim that the formula fails one unit outside them.
  • The calculation is deterministic: the same inputs always give the same result. It carries no allowance for machine condition, operator skill, ambient conditions or lot-to-lot material variation unless an input above explicitly represents one.
  • Nothing is sent anywhere. The maths runs in your browser, so the numbers you type never leave the page.

Standards and further reading

  • ISO 6552 / ISO 6553 - automatic steam traps, definitions and marking.
  • BS 845 - methods for assessing thermal performance of boilers, for the fuel-side figures.
  • ASME PTC 39 - Steam Traps, performance test code.
  • Napier equation for choked steam flow through an orifice, as used in ISO 6552 loss assessment.

Questions people ask

Why does downstream pressure not appear in the formula?

Because the flow is choked. Once the upstream absolute pressure is more than about 1.9 times the downstream, the steam reaches sonic velocity in the orifice throat and the mass flow stops responding to anything downstream - it is set by the upstream pressure and the area alone. For a trap discharging to atmosphere or to a condensate main at low pressure, any line above roughly 1 bar gauge is choked, which covers essentially all mill distribution. Below that the flow becomes subsonic and this expression overstates it.

How would anyone know 12 traps have failed?

They would not, without looking - which is the point. A failed-open trap gives no visible plume if it discharges into a closed condensate return, makes no alarm, and does not stop production. It is found by survey: ultrasonic listening, thermal imaging or a temperature difference across the trap, typically at a few minutes per trap. Survey findings across unmanaged plants cluster around 10 to 20% failed, so a mill with 100 traps and no programme should assume something like this figure until it has measured otherwise.

Is a failed-closed trap not worse?

Different, and usually cheaper but more disruptive. A trap failed closed backs condensate up into the equipment, which shows immediately as loss of heating capacity - a stenter chamber that will not reach temperature, a cylinder that dries unevenly. It gets fixed because production complains. The failed-open trap is the expensive one precisely because nothing complains: capacity is unaffected, the only symptom is the fuel bill, and it can run for years. That asymmetry is why surveys pay.

Convert this result

Reference rate of 2026-10-05, published by the European Central Bank. Source

A reference rate is not a dealing rate. Banks and payment providers apply their own spread, so treat this as the mid-market figure a quotation is negotiated around rather than the money that will arrive.

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